创建进程和重定向输出

有 2 个应用程序。

AppCMD是一个命令行应用程序，AppMAIN使用一些命令行参数开始AppCMD。 不幸的是，AppMAIN似乎不能很好地处理输出AppCMD并且出了点问题。

我想记录对AppCMD及其输出的调用，以查看发生了什么。

为此，我想将AppCMD替换为另一个二进制AppWRAP，该将调用转发到重命名的AppCMD并记录其输出。AppWRAP应该表现得像一个透明的中间人。

出于测试目的，我编写了一个简单的AppCMD，只输出它的命令行参数：

#include <iostream>
using namespace std;
int main(int argc, char *argv[])
{
cout << "#### Hello, I'm the test binary that wants to be wrapped." << endl;
if (argc < 2) {
cout << "#### There where no command line arguments." << endl;
}
else {
cout << "#### These are my command line arguments:";
for (int i = 1; i < argc; ++i) cout << " " << argv[i];
cout << endl;
}
cout << "#### That's pretty much everything I do ... yet ;)" << endl;
return 0;
}

我遵循 MSDN：使用重定向输入和输出创建子进程来实现AppWrap但我卡住了，因为它没有返回，我无法弄清楚为什么：

#include <iostream>
#include <sstream>
#include <Windows.h>

using namespace std;

const string TARGET_BINARY("TestBinary.exe");
const size_t BUFFSIZE = 4096;
HANDLE in_read        = 0;
HANDLE in_write       = 0;
HANDLE out_read       = 0;
HANDLE out_write      = 0;
int main(int argc, char *argv[])
{
stringstream call;
cout << "Hello, I'm BinTheMiddle." << endl;
//-------------------------- CREATE COMMAND LINE CALL --------------------------
call << TARGET_BINARY;
for (int i = 1; i < argc; ++i) {
call << " " << argv[i];
}
cout << "Attempting to call '" << call.str() << "'" << endl;
//------------------------------ ARRANGE IO PIPES ------------------------------
SECURITY_ATTRIBUTES security;
security.nLength              = sizeof(SECURITY_ATTRIBUTES);
security.bInheritHandle       = NULL;
security.bInheritHandle       = TRUE;
security.lpSecurityDescriptor = NULL;
if (!CreatePipe(&out_read, &out_write, &security, 0)) {
cout << "Error: StdoutRd CreatePipe" << endl;
return -1;
}
if (!SetHandleInformation(out_read, HANDLE_FLAG_INHERIT, 0)) {
cout << "Stdout SetHandleInformation" << endl;
return -2;
}
if (!CreatePipe(&in_read, &in_write, &security, 0)) {
cout << "Stdin CreatePipe" << endl;
return -3;
}
if (!SetHandleInformation(in_write, HANDLE_FLAG_INHERIT, 0)) {
cout << "Stdin SetHandleInformation" << endl;
return -4;
}
//------------------------------ START TARGET APP ------------------------------
STARTUPINFO         start;
PROCESS_INFORMATION proc;
ZeroMemory(&start, sizeof(start));
start.cb         = sizeof(start);
start.hStdError  = out_write;
start.hStdOutput = out_write;
start.hStdInput  = in_read;
start.dwFlags    |= STARTF_USESTDHANDLES;
ZeroMemory(&proc, sizeof(proc));
// Start the child process.
if (!CreateProcess(NULL, (LPSTR) call.str().c_str(), NULL, NULL, TRUE,
0, NULL, NULL, &start, &proc))
{
cout << "CreateProcess failed (" << GetLastError() << ")" << endl;
return -1;
}
// Wait until child process exits.
WaitForSingleObject(proc.hProcess, INFINITE);
// Close process and thread handles.
CloseHandle(proc.hProcess);
CloseHandle(proc.hThread);
//----------------------------------- OUTPUT -----------------------------------
DWORD dwRead;
CHAR  chBuf[127];
while (ReadFile(out_read, chBuf, 127, &dwRead, NULL)) {
cout << "Wrapped: " << chBuf << endl;
}
return 0;
}

好像在等ReadFile回来。谁能发现我做错了什么？

我这样称呼二进制文件：

> shell_cmd_wrapper.exe param1 param2

这是控制台输出，但二进制文件不返回。

Hello, I'm BinTheMiddle.
Attempting to call 'TestBinary.exe param1 param2'
Wrapped:#### Hello, I'm the test binary that wants to be wrapped.
#### These are my command line arguments: param1 param2
#### That'sD
Wrapped: pretty much everything I do ... yet ;)
s to be wrapped.
#### These are my command line arguments: param1 param2
#### That'sD

(请忽略我不清除缓冲区)