如果没有数学库，我如何在C++中创建复利公式

How can I create the compound interest formula in C++ without a math library?

本文关键字：创建 C++ 如果没有      更新时间：2023-10-16

我一直试图完成一项需要运行复利公式的作业，但我只能使用iomainip和iostream库。

do (cout << BaseMembershipFee * pow((ONE+(GoldRate/CompoundMonthly),(CompoundMonthly*years)) << years++) << endl;
while (years < 11);

这适用于数学库(我想(，但我不知道如何在没有pow的情况下制作它。

变量：

const float BaseMembershipFee = 1200, GoldRate = 0.01, CompoundMonthly = 12, ONE = 1;
float years = 1;

在您的问题中，它指出年份=1。根据do while((循环，我怀疑您的意思是显示年份=10。

下面的代码有一个函数可以计算每个期间的复利，在您的情况下是每个月。

然后，因为看起来你被要求在每年年底计算中期金额，我们有第二个循环。

#include<iostream>
float CompountInterestMultiplier(float ratePerPeriod, float periods) {
float multiplier = 1.0;
for (int i = 0; i < periods; i++) {
multiplier *= (1.0 + ratePerPeriod);
}
return multiplier;
}
int main() {
const float BaseMembershipFee = 1200;
const float GoldRate = 0.01;  // represents annual rate at 1.0%
const float periodsPerYear = 12.0;  // number of compounds per year.  Changed the name of this from compoundsMonthly
const float ONE = 1.0;              // Did not use this
const float years = 10.0;     // I think you have a typo 
// and wanted this to be 10
float ratePerPeriod = GoldRate / periodsPerYear;
// If you want to print the value at the end of each year, 
// then you would do this:
float interimValue = BaseMembershipFee;
for (int year = 0; year < 11; year++) {
interimValue = BaseMembershipFee *
CompountInterestMultiplier(ratePerPeriod, periodsPerYear * year);
std::cout << "Value at end of year " << year << ": $" << interimValue << std::endl;
}
}

Here is the output:
Value at end of year 0: $1200
Value at end of year 1: $1212.06
Value at end of year 2: $1224.23
Value at end of year 3: $1236.53
Value at end of year 4: $1248.95
Value at end of year 5: $1261.5
Value at end of year 6: $1274.17
Value at end of year 7: $1286.97
Value at end of year 8: $1299.9
Value at end of year 9: $1312.96
Value at end of year 10: $1326.15
Process finished with exit code 0
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