C++ 候选构造函数不可行:没有已知的转换

C++ Candidate constructor not viable: no known conversion

本文关键字：转换 候选 构造函数 不可行 C++      更新时间：2023-10-16

这是一个PNG类，在类文档中列出了两个构造函数。

PNG::PNG    (   string const &  file_name   )   
Creates a PNG image by reading a file in from disk.
Parameters
file_name   Name of the file to be read in to the image.
PNG::PNG    (   size_t  width, size_t   height )        
Creates a default PNG image of the desired dimensions (that is, a width x height opaque white image).
Parameters
width   Width of the new image.
height  Height of the new image.

我使用以下方法来调用构造函数：

int main(){
    PNG in_image=new PNG("in.png");
    size_t width=in_image.width();
    size_t height=in_image.height();
    PNG out_image=new PNG(width,height);
}

但是在下面出现错误：

main.cpp:5:6: error: no viable conversion from 'PNG *' to 'PNG'
    PNG in_image=new PNG("in.png");
        ^        ~~~~~~~~~~~~~~~~~
./png.h:62:9: note: candidate constructor not viable: no known conversion from
  'PNG *' to 'const PNG &' for 1st argument; dereference the argument with *
    PNG(PNG const & other);
    ^
./png.h:55:9: note: candidate constructor not viable: no known conversion from
  'PNG *' to 'const string &' (aka 'const basic_string<char,
  char_traits<char>, allocator<char> > &') for 1st argument
    PNG(string const & file_name);
    ^
main.cpp:8:6: error: no viable conversion from 'PNG *' to 'PNG'
    PNG out_image=new PNG(width,height);
        ^         ~~~~~~~~~~~~~~~~~~~~~
./png.h:62:9: note: candidate constructor not viable: no known conversion from
  'PNG *' to 'const PNG &' for 1st argument; dereference the argument with *
    PNG(PNG const & other);
    ^
./png.h:55:9: note: candidate constructor not viable: no known conversion from
  'PNG *' to 'const string &' (aka 'const basic_string<char,
  char_traits<char>, allocator<char> > &') for 1st argument
    PNG(string const & file_name);

谁能就我的构造函数调用有什么问题给出一些提示？感谢

你应该这样写： 

PNG *in_image=new PNG("in.png");
size_t width=in_image->width();
size_t height=in_image->height();
PNG *out_image=new PNG(width,height);

使用 new 应该会得到一个PNG*，即指向对象的指针。

你应该这样写：

PNG in_image("in.png");
size_t width = in_image.width();
size_t height = in_image.height();
PNG out_image(width, height);

C++不是Java-您可以使用new来动态分配对象，但是当您不这样做时，您不会使用它。除非你真的需要它，否则你不应该使用new。

类型X运算符new将为X分配内存并返回其类型为X*的地址。
所以你应该把它收集在一个指针变量中：

PNG* in_image = new PNG("in.png");        // in_image points to the newly created PNG object
size_t width = in_image.width();
size_t height = in_image.height();
PNG* out_image = new PNG(width,height);   // another object is created and out_image points to it
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